this post was submitted on 02 Apr 2026
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[–] vithigar@lemmy.ca 5 points 2 hours ago (2 children)

...how does 36KB RAM and 72KB ROM give you a total of 64KB?

[–] Michal@programming.dev 5 points 44 minutes ago* (last edited 43 minutes ago)

Space dilation.

[–] captain_aggravated@sh.itjust.works 1 points 4 minutes ago

The AGC had 2048 words of erasable core storage, what we'd now call RAM, and 36,864 words of read only core rope memory. So a total of 38,912 words. Each word is 15 bits plus a parity bit, so that'd work out to 75,776 bytes or 72,168 bytes depending on whether you count parity or not, and then kilobytes, kibibytes...it's closer to 64k than 32 or 128.