this post was submitted on 30 Aug 2025
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The point with digital transfers is that you round it back to either 0 or 1, hoping that no bits are distorted enough to have any loss at all.
Exactly. Digital logic, when implemented in analogue, generally have to have forbidden zones where a signal in that range is considerer invalid. Regardless of implementation, digital is about the discretized logic of the system. That is explicitly the whole point of digital: Minor analogue distortion does not change the information content of the signal unless it is so bad as to flip a bit.
This isn’t true in the general case. In the real world, you can have all kinds of distortions: random noise, time shifts, interference from other signals, etc.
You don’t usually see the effects of these because the protocols are designed with the communication channel characteristics in mind in order to reproduce the original signal.
Using birds is just another communication channel with its own distortion characteristics.
Precisely... And digital modulation's entire purpose is for a digital signal to survive those distortions bit-for-bit perfect. Even if we call the digitally-generated spectrogram digital information, the bird simply did not reproduce it exactly. Whatever time, frequency, and amplitude resolution you apply to the signal, if it's low enough that the bird reproduced the signal exactly within that discretized scheme, then it simply did not achieve 2 MB/s. I would bet that the Shannon capacity of this bird is simply nowhere near 2 MB/s.
If your argument is that the bandwidth calculation is incorrect, then sure I think that’s fair.
But I don’t think it’s correct to say it’s not a digital channel juts because it doesn’t have optimal bandwidth.
It isn't a digital channel because it does not reproduce digital data. Unless it's a one-bit signal of "does this look like a bird? yes/no", but then the human making that assessment is part of the channel. To claim this is a digital system would require us to be so reductive as to redefine the meaning of the word.
If we’re being pedantic, shouldn’t we consider that it can be a one bit signal? Otherwise you should be specific about what bandwidth you’d consider digital.
Gozz is correct. You're misunderstanding the nature of a digital signal. What the author did was convert a digital signal to an analog signal, store that analog signal on a bird, then record that analog signal. Whether it was redigitized after the fact is irrelevant. It is not a digital process end-to-end. This is the same as if I were to download a YouTube video, record that video on a VHS tape, then redigitize that video. Not only would the end result not be a bit for bit match, it wouldn't be a match at all despite containing some of the same visual information, because it would be the product of a digital-analog-digital conversion.
The bird drawing is just a proxy for arbitrary data. In your example, you could convert bitstream into a pattern of black and white squares into a YouTube Video. Send it through the VHS channel, and when you digitize it, you would get back the exact bitstream.
Yes, that would be a digital modulation. That is decidedly not what is being done with the bird. The input data is the "PNG" of the bird, which is then not digitally modulated, but converted to an analogue signal and later redigitized. If the file has been converted to a series of pulses at different frequencies (the equivalent of your black and white squares) that would be a digital modulation. I am not arguing that this is not possible. My original comment explicitly says I would like to see a follow up with actual modulation. But just because it is possible to run dialup over an analogue phone line does not mean that calling your grandma on that same phone is a digital communication system. Some computers back in the day could modulate and record data on commercial audio cassettes. That does not mean that if I record something off the radio and play it back later that's a digital copy of the song.