this post was submitted on 19 Feb 2025
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[–] Cyber@feddit.uk 1 points 6 months ago

Not sure what to make of this, they've got the potential to put a million qubits on a chip, but there's only 8...

And others have had quantum computers for a while now... so... πŸ€·πŸΌβ€β™‚οΈ

[–] troyunrau@lemmy.ca 1 points 6 months ago

I'll believe it when I see code written for it solving a real problem

[–] archomrade@midwest.social 0 points 6 months ago (1 children)

Microsoft isn’t using electrons for the compute in this new chip; it’s using the Majorana particle that theoretical physicist Ettore Majorana described in 1937.

Ok now i'm gonna need an explain-like-i'm-not-a-quantum-scientist on what a 'topological transistor' is, and what it uses instead of electrons for its compute (and, like, what is the significance?)

[–] Dudewitbow@lemmy.zip 0 points 6 months ago (1 children)

to most people (including myself, who did take college level modern physics. course), explaining the standard model of elementary particles, is way too high of a level regardless.

its like being given scifi names and terminology, and then suddenly finding out theyre real.

[–] archomrade@midwest.social 0 points 6 months ago (1 children)

Lmao, yea I think they're kind of playing a game with language here.

After doing some reading of various explanations, what they mean when they say they aren't using electrons for computation is basically that the 'thing' they're measuring that dictates the 'state' of the transistor is a quasi-particle..... but that particle is only observed through the altered behavior of electrons (i guess in the case of the majorana particle, it appears as two electrons gathered together in synchrony?)

So the chip is still using electrons in its computation in the same say as a traditional transistor - you are still sending electrons into a circuit, and the 'state' of the bit is determined by the output signal. It's just that, in this case, they're looking for specific behavior of the electrons that indicate the presence and state of this 'qbit'

That is just my layman's understanding of it

[–] straightjorkin@lemmy.world 1 points 6 months ago

So much of modern tech is just misusing words they heard from sci-fi stuff that was already misusing words they heard in physics class.

[–] MCasq_qsaCJ_234@lemmy.zip 0 points 6 months ago (1 children)
[–] AbouBenAdhem@lemmy.world 1 points 6 months ago

As long as you don’t observe it.